Calculate the approxiimate number of unit cells present in 1g of gold. It is well known that gold crystallises in the face cubic lattice (atomic mass of gold is 197u).

Calculate the approxiimate number of unit cells present in 1g of gold.

1.	Calculate the approxiimate number of unit cells present in 1g of gold. It is well known that gold crystallises in the face cubic lattice (atomic mass of gold is 197u).
Answer» `7.64xx10^(20)` `6.02xx10^(23)` 197 4 Solution :(a) 1 mole of GOLD=197g=`6.02xx10^(23)` atoms. Number ofatomsavailable in 1g of gold =`(6.02xx10^(23))/(197)` As FCC unit CELL contains 4 atoms. Number of unit cells present=`(6.02xx10^(23))/(197xx4)=7.64xx10^(20)`