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Calculate the approxiimate number of unit cells present in 1g of gold. It is well known that gold crystallises in the face cubic lattice (atomic mass of gold is 197u).A. `7.64xx10^(20)`B. `6.02xx10^(23)`C. 197D. 4

Answer» (a) 1 mole of gold=197g=`6.02xx10^(23)` atoms.
Number of atoms available in 1g of gold =`(6.02xx10^(23))/(197)`
As fcc unit cell contains 4 atoms.
Number of unit cells present=`(6.02xx10^(23))/(197xx4)=7.64xx10^(20)`


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