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Calculate the approximate number of unit cells present in 1 g of ideal NaCl crystals. |
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Answer» Solution :1 mole of NaCl=58.5 g =`6.02xx10^23` FORMULA units. `therefore` No. of formula units in 1 g of NaCl=`(6.02xx10^23)/58.5` As ONE unit cell of NaCl contains 4 NaCl formula units, therefore, NUMBER of unit CELLS PRESENT in 1 g of NaCl =`(6.02xx10^23)/(58.5xx4)=2.57xx10^21` |
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