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Calculate the area of the parallelogram whose two adjacent sides are formed by the vectors `vec A xx 4 hat I + 3 hat j and vec B =- 3 hati +6 hat j. |
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Answer» `vec A xx vecB =|(hat i,hat j,hatk,), (4,3,o),(-3, 6, 0)| =hati (3 xx0-6xx o) +hatj [0 xx(-3) -0xx 4 ] + hat k [4 xx 6-3 xx (-3)] =33 hatk` Area of parallelogram `=|vecA xx vec B| =sqrt (0^(2)0^(2) +(33)^(2) ) =33 sq a for vec F =(-3 hati +hat j [0xx (-3) -0 xx 4] + hat k [4 xx 6- 3 xx (-3) ] =33 hat k` Area of parallelogeam `=|vec A xx vec B| =sqrt(0^(2) +0^(2)+33)^(2)) =33 sq. units`. |
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