Calculate the area of the quadrilateral ABCD as shown in Fig., given t

1.	Calculate the area of the quadrilateral ABCD as shown in Fig., given that BD = 42 cm, AC = 28 cm, OD = 12 cm and AC ⊥ BO.
Answer» BD = 42 cm, AC = 28 cm, OD= 12 cm Area of Triangle ABC = 1/2 (AC x OB) = 1/2 (AC x (BD – OD)) = 1/2 (28 cm x (42 cm – 12 cm)) = 1/2 (28 cm x 30 cm) = 14 cm x 30 cm = 420 cm² Area of Triangle ADC = 1/2 (AC x OD) = 1/2 (28 cm x 12 cm) = 14 cm x 12 cm = 168 cm² Hence, Area of the quadrilateral ABCD = Area of ABC + Area of ADC = (420 + 168) cm² = 588 cm²

Calculate the area of the quadrilateral ABCD as shown in Fig., given that BD = 42 cm, AC = 28 cm, OD = 12 cm and AC ⊥ BO.

Answer»

BD = 42 cm, AC = 28 cm, OD= 12 cm

Area of Triangle ABC = 1/2 (AC x OB)

= 1/2 (AC x (BD – OD))

= 1/2 (28 cm x (42 cm – 12 cm))

= 1/2 (28 cm x 30 cm)

= 14 cm x 30 cm

= 420 cm²

Area of Triangle ADC = 1/2 (AC x OD) = 1/2 (28 cm x 12 cm)

= 14 cm x 12 cm

= 168 cm²

Hence, Area of the quadrilateral ABCD = Area of ABC + Area of ADC

= (420 + 168) cm²

= 588 cm²