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Calculate the area of the triangle for which two of its sides are given by the vectors vecA=5hati-3hatj, vecB=4hati+6hatj. |
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Answer» Solution :AREA of the TRIANGLE `=(1)/(2)|barAxxbarB|` `barAxxbarB=|{:(HATI,hatj,hatk),(5,-3,0),(4,6,0):}|=hati(0)+hatj(0)+hatk(30+12)=42hatk` `|barAxxbarB|=sqrt(42^(2))=42` `:.` Area of the triangle `=(1)/(2)|barAxxbarB|=(1)/(2)xx42` Area =21 squared units |
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