1.

Calculate the average kinetic energy (in joule) per molecule in `8.0 g` of methane at `27^(@)C`.A. `6.21 xx10^(-20) J// "molecule"`B. `6.21 xx10^(-21) J// "molecule"`C. `6.21 xx10^(-22) J// "molecule"`D. `3.1 xx10^(-22) J// "molecule"`

Answer» Correct Answer - B
Average `KE=(3)/(2)xx(8.314)/(6.023xx10)^(23)`
`6.21xx10^(-21)J//"molecule"`


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