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Calculate the average kinetic energy in joules of the molecules in 8.0 g of methane at 27^@C. |
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Answer» `K.E. = n(3/2 RT)` Number of moles in 8.0 g of methane = `(8.0)/16 = 0.500` (The molecular MASS of `CH_4 = 12 +4 = 16)` `R = 8.314 J K^(-1) mol^(-1)` Hence, the average kinetic energy of 0.5 moles of `CH_4 at 27^@C`. = `0.500 XX 3/2 xx 8.314 xx (27 + 273) = 1.87 x 10^3 J` |
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