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Calculate the average kinetic energy of a hydrogen molecule at 27^@C. |
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Answer» SOLUTION :The average KINETIC ENERGY of a SINGLE molecule is given by `E_x = 3/2 KT` `:.`Average kinetic energy of a hydrogen molecule at at `27^@(300 K)` `=3/2xx1.3807 x 10^(-23) xx 300` ( `:. k = 1.3807 xx 10^(-23) JK^(-1))` = `6.231 xx 10^(-21) J` |
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