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Calculate the binding energy per nucleon for `C^(12),N^(14), O^(16)`, and comment on their relative magnitudes. Masses of proton and neutron are `1.0078` and `1.0087m_(u)`, respectively. `(m_(u)=931MeV)` |
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Answer» Correct Answer - `C^(12)=7.68MeV` `N^(14)=7.68MeV` `O^(16)=7.68MeV` Stability is same. `a. C^(12),` proton `=6`, neutron `=6` `Delta_(m)=(6xx1.0078+6xx1.0087)-12` `=(6.0468+6.0522)-12` `=12.099-12=0.099m _(u)` `BE` per nucleus `=(0.099xx931)/(12)MeV=7.68MeV` `b.` `N^(14), proton =7`, neutron `=7` `Delta m=(7xx1.0078+7xx1.0087)-14` `=(7.0546+7.0609)-14` `=14.1155-14=0.1155m_(u)` `BE` per nucleus `=(0.1155xx931)/(14)MeV=7.68m_(u)` `c.` `O^(16),` proton `=8` neutron `=8` `Delta_(m)=(8xx1.0078+8xx1.0087)-16` `=(8.0624+8.0696)-16` `=0.132m_(u)` `BE` per nucleus `=(0.132xx931)/(16)MeV=7.68MeV` |
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