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Calculate the binding energy per nucleon of `Li` isotope, which has the isotopic mass of `7.016 am u`. The individual masses of neutron and proton are `1.008665 am u` and `1.007277 am u`, respectively and the mass of electron `= 0.000548 am u`. |
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Answer» Correct Answer - `5.6MeV` Nuclear binding energy `:` The nuclear binding energy can be defined in the following ways `:` `a.` The energy needed to break a nucleus into its constituent nucleons `(` isolated protons and neutrons `0` is called nuclear binding energy. `b.` The energy liberated when nucleons get packed together to form the nucleus is called nuclear binding energy. `c.` The energy equivalent of mass defect `(DeltaE=Deltamc^(2))` in the formation of nucleus from protons and neutrons is called nuclear binding energy. Num `:` Lithium nuclei `._(3)Li^(7)` Number of protons `=3 ` Number of neutrons `=703=4` Mass defect `=Deltam=[Zm_(H)+(A-Zm_(n)]-M` `Deltam=3xx1.007277+4xx1.008665-7.016` `=3.021831+4.03466-7.016` `=7.056491-7.016` `=0.040491 am u` Total Be `=0.040491xx931.5` `=37.717MeV`. `BE//` nucleon`=(37.717)/(7)=5.6MeV` |
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