1.

Calculate the boiling point of a solution which is prepared by dissolving 68.4g of solute B in one kilogram of water . (Molar mass of solute B is 342 gmol^(-1) T_b=373.1 K and K_b (water ) = 0.52 Kkg mol ^(-1)

Answer»

SOLUTION :` W_1 "" 1KG `
` W_2 ""= 68.4g`
`M_2 "" =342 g MOL^(-1) `
` T_b "" =373.1K`
` K_b "" = 0.52K.kg mol ^(-1) `
` T-T_b "" = K_b m `
`m ""= 0.2`
` T-T^(@) "" K_bxxm `
` T-T^(@) =0.52 XX 0.2`
` T-T^(@) =0.104`
` T-373.1 =0.101`
`T ="" 0.101+373.1`
` T""= 373.204`


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