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Calculate the boiling point of a solution which is prepared by dissolving 68.4g of solute B in one kilogram of water . (Molar mass of solute B is 342 gmol^(-1) T_b=373.1 K and K_b (water ) = 0.52 Kkg mol ^(-1) |
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Answer» SOLUTION :` W_1 "" 1KG ` ` W_2 ""= 68.4g` `M_2 "" =342 g MOL^(-1) ` ` T_b "" =373.1K` ` K_b "" = 0.52K.kg mol ^(-1) ` ` T-T_b "" = K_b m ` `m ""= 0.2` ` T-T^(@) "" K_bxxm ` ` T-T^(@) =0.52 XX 0.2` ` T-T^(@) =0.104` ` T-373.1 =0.101` `T ="" 0.101+373.1` ` T""= 373.204` |
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