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Calculate the boiling point of an aqueous solution containing 1of MgBr, in 200 g of water. (Atomic mass : Mg 24, Br 80)(K, for H20 0.52 K kg mol-1).0.50 g2 |
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Answer» DTf= kf*m dTf= 0.512*(10.50/184)1000/200=0.146’C dTf=freezing pt. of pure water- Freezing pt. of solution 0.146=0’C-Freezing pt. of solution Freezing pt. of solution(containing MgBr2)=-0.146’C |
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