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Calculate the bond order of Helium. |
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Answer» Solution :HELIUM contains four electrons. Its ELECTRONIC configuration is `H^(+)_(2)` Bond ORDER `=(1)/(2)(n_(b)-n_(a))` `n_(b)=` number of anti bonding electrons `(1)/(2)(2-2)=0` So, `He_(2)`, dons not EXIST. |
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