1.

Calculate the capacitance of a capacitor that stores 40microC of charge and has a voltage of 2V.(a) 20F(b) 20microF(c) 10F(d) 10microF

Answer» Right option is (b) 20microF

To elaborate: Q is directly proportional to V. The constant of proportionality in this case is C, that is, the capacitance. Hence C=Q/V.

C=40microC/2V=20microF.


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