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Calculate the capacity of unknown capacitance is connected acrosss a battery of V volts. The charge stored in it is `360 muC`. When potential across the capacitor is reduced by 120V, the charge stored in it becomes `120 muC`. Calculate (i) the potential V and unknown capacitance C. (ii) What will be the charge stored in the capacitor. If the voltage applied had increased by 120 V |
Answer» From the relation `Q=CV=360 mu C` When potential is reduced to 120V `120 mu C= C( V-120) = 120 C` `rArr" " 120 mu C = 360 mu C- 120 C rArr " "120=240 mu C` `rArr C=(cancel (240)muC)/cancel (120)=2 mu F` Potential `V= (360 mu C)/(2 mu F) = 180 V` Charged stored when voltage applied is increased by `120V Q ^(1)=2 mu F xx (180V + 120 V) = 600 mu C` |
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