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Calculate the cell potential E at `25^(@)` C for the reactioni : `2Al(s) + 3Fe^(2+)(aq) rightarrow 2Al^(3+)(aq) + 3Fe(s)` [Given : `[Fe^(2+)] = 0.01M, [Al^(3+)] = 0.10M,` `E^_(Fe^(+2)//Fe)^(@) = -0.45V and ((2.303Rt)/(F) = 0.06)`A. `+1.20V`B. `+1.16V`C. `+1.24V`D. `+1.12V` |
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Answer» Correct Answer - B |
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