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Calculate the change in current in an inductor having inductance 4000H, number of turns is 200 and the flux changes from 760 to 800 Wb.(a) 2A(b) 4A(c) 6A(d) 8A |
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Answer» Correct answer is (a) 2A The best I can explain: From the formula of incremental inductance, we know that: L=(Change in flux/Change in current)*Number of turns Substituting the values from the given question, we get a change in current = 2A. |
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