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Calculate the change in intensity level when the intensity of sound increases by 10^(6) times its original intensity. |
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Answer» SOLUTION :Here, `(I)/(I_(0))=("Final INTENSITY")/("Original intensity")=10^(6)` INCREASE in intensity level, `:.L=10log_(10)((I)/(I_(0)))` `=10log_(10)(10^(6))=10xlog_(10)(10^(6))` `=10xx6xx1` `impliesL=60` DECIBEL |
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