Calculate the change in pH of water when 0.01 mole of NaOH are added i

1.	Calculate the change in pH of water when 0.01 mole of NaOH are added in 10 litre water.
Answer» Solution :PH of water is 7 `M= ("no . of moles ")/(" sol . of solution (lit) ") =( 0.01)/(10 ) = 10 ^(_3) ` ` pOH=3, pH =11 , "change in pH"= 11- 7= 4`

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