Calculate the change in weight of a 20 kg body, when it is taken from equator to pole of earth.

Calculate the change in weight of a 20 kg body, when it is taken from

1.	Calculate the change in weight of a 20 kg body, when it is taken from equator to pole of earth.
Answer» SOLUTION :At EQUATOR `g_(e) = g - R omega^(2)` At pole `g_(P) = g` THEREFORE, `mg_(e) - mg_(P) = m(g_(e) - g_(P))` `=20(g - R omega^(2) - g)` `= 20 R omega^(2)` (IGNORING negative sign) `mg_(e) - mg_(P) = 20 xx R omega^(2) = 20 xx R xx (4pi^(2))/(T^(2))` `= (20 xx 6,400 xx 1,000 xx 4 xx 3.14 xx 3.14)/((24 xx 3,600)^(2))` = 0.676 N