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Calculate the charge in coloumbs required for oxidation of 2 moles of water to oxygen ? (Given 1 F=96,500 C `mol^(-1)`) |
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Answer» The oxidation reaction is : `underset(2"mol")(2H_(2)O)to4H^(+)+O_(2)+underset(4F)4e^(-)` Change in coloumbs (Q)`=4F=4xx(96500" C")=386000" C"` |
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