1.

Calculate the coefficient of correlation using Karl Pearson's formula of the series given below:

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Solution :
`bar(X)=(sumX)/(N)=(80)/(5)=16,bar(Y)=(sumY)/(N)=(100)/(5)=20`
`r=(sumxy)/(sqrt(sumx^(2)xxsumy^(2)))`
Here, `sumxy=84,sumx^(2)=118,sumy^(2)=80`
Substituting the values, we get
`r=(84)/(sqrt(118xx80))=(84)/(sqrt(9,440))`
`=(84)/(sqrt(97.16))=0.864`
COEFFICIENT of Correlation (r)=0.864.


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