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Calculate the coefficient of real expansion from the following data. Weight of the specific gravity bottle = 40.25 gm , Weight of the bottle + liquid at 25^(@)C = 70.50 gm Weight of the bottle + liquid at 100^(@)C 69.20gm : Coefficient of linear expansion of glass = 0.000009//^(@)C |
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Answer» Solution :`w _(1) = 40.25 gm, w _(2) = 70 . 50 gm and w _(3) = 69.20 cm,t _(1) ^(@) C = 25 ^(@) C and t _(2) ^(@) C = 100^(@)C` Coefficient of apparent ecxpansion of the liquid, `GAMMA _(a) = (w _(2) - w _(3))/( (w _(3) - w _(1)) (t_(2) -t _(1)))` ` = (70. 50 - 69.20)/( (69. 20 - 60.25) (10 0-25))= (1.30)/(28. 95 xx 75)= (1.30)/( 2171.25) = 0.0005987//^(@)C` `gamma _(gamma) = 3 alpha = 3 xx 0.000009 = 0.000027^(@)C ^(-1)` `gamma _(a) = 0.0005987 + 0.000027 = 0.0006327^(@)C ^(-1) ~~6.26 xx 10 ^(-4) //^(@)C ^(-1)` |
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