Calculate the concentration of nitric acid in moles per litre in a sam

1.	Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g mL-1 and the mass percent of nitric acid in it being 69%.
Answer» 69 mass percent of nitric acid means that 69 g of HNO₃ are present in 100 g of solution. Volume of solution = Mass/Density = 100g/1.41mL⁻¹ = 70.92 mL Moles of HNO₃= 69/63 = 1.095 Therefore Molarity = Moles of HNO₃ /Volume of solution (in ml ) x 1000 = 1.095/70.92 x 1000 = 15.44 M

Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g mL-1 and the mass percent of nitric acid in it being 69%.

Answer»

69 mass percent of nitric acid means that 69 g of HNO₃ are present in 100 g of solution.

Volume of solution = Mass/Density = 100g/1.41mL⁻¹ = 70.92 mL

Moles of HNO₃= 69/63 = 1.095

Therefore Molarity = Moles of HNO₃ /Volume of solution (in ml ) x 1000 = 1.095/70.92 x 1000 = 15.44 M