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| 1. |
Calculate the correlation cofficient beteen X and Yand comment on their relationship . |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/TRJ_ECO_XI_C12_E01_093_S01.png" width="80%"/> <br/> `r=(sumdxdy-((sumdx)xx(sumdy))/(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>))/(sqrt(sumdx^(2)-((sumdx)^(2))/(N)xxsqrt(sumsy^(2)-((sumdy)^(2))/(N))` <br/> `r=(68-((-2)xx(-4))/(6))/(sqrt(34-((-2)^(2))/(6))xxsqrt(136xx((-4)^(2))/(6))` <br/> `(68-(8)/(6))/(sqrt(34-(4)/(6))xxsqrt(136-(16)/(6)))` <br/> `=((408-8)/(6))/(sqrt((204-4)/(6))xxsqrt((816-16)/(6)))` <br/> `=((400)/(6))/(sqrt((200)/(6))xxsqrt((<a href="https://interviewquestions.tuteehub.com/tag/800-338448" style="font-weight:bold;" target="_blank" title="Click to know more about 800">800</a>)/(6)))` <br/> `((400)/(6))/((1)/(6)sqrt(200xx800))` <br/> `(400)/(6)xx(6)/(1)xx(1)/(sqrt(1,60,000))` <br/> `(400)/(400)=1` <br/> <a href="https://interviewquestions.tuteehub.com/tag/correlation-935534" style="font-weight:bold;" target="_blank" title="Click to know more about CORRELATION">CORRELATION</a> coefficient (r)=1 <br/> This is a situation of a <a href="https://interviewquestions.tuteehub.com/tag/perfectly-7309466" style="font-weight:bold;" target="_blank" title="Click to know more about PERFECTLY">PERFECTLY</a> positive correlation between X and Y.</body></html> | |