Saved Bookmarks
| 1. |
Calculate the correlation cofficient between the heights of Fathers in inches (X) and their sons (Y). |
Answer» Solution : `R=(sumdxdy-((sumdx)xx(sumdy))/(N))/(SQRT(sumdx^(2)-((sumdx)^(2))/(N)xxsqrt(sumdy^(2)-((sumdy)^(2))/(N))` `=(118-(-10)xx(-36)/(8))/(sqrt(156-(-10)^(2))/(8))xxsqrt((36)^(2))/(8))` `=(118-45)/(sqrt(156-12.5)xxsqrt(356-162))` `=(73)/(sqrt(143.5)xxsqrt(194))` `=(73)/(11.98xx13.93)` `=(73)/(166.88)=0.44` Correlation coefficient (r)=0.44 |
|