Calculate the de-Brogile wavelength of the elctron orbiting in the `n=2` state of hydrogen atom.

Calculate the de-Brogile wavelength of the elctron orbiting in the `n=

1.	Calculate the de-Brogile wavelength of the elctron orbiting in the `n=2` state of hydrogen atom.
Answer» Energy in orbit for which `n=2`. `E=(-13.6)/(2^(2))eV=-3.4eV` Now, `3.4xx1.6x10^(-19)=(hc)/(lambda)implies=(6.6xx10^(-34)xx3xx10^(8))/(3.4xx1.6xx10^(-19))=3.639xx10^(-7)=3639Å`.

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Calculate the de-Brogile wavelength of the elctron orbiting in the `n=2` state of hydrogen atom.

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