Calculate the degree of dissociation ofHI at 450^(2)Cif the equilibrium constant for the dissociation reaction is 0.263

Calculate the degree of dissociation ofHI at 450^(2)Cif the equilibriu

1.	Calculate the degree of dissociation ofHI at 450^(2)Cif the equilibrium constant for the dissociation reaction is 0.263
Answer» Solution :SUPPOSE we start with 1 mole of HI and x is the degree of dissociation. Then at EQUILIBRIUM, `[HI] = (1-x) //V, [H_(2)]= x//2 V and [I_(2)] = x//2" moles per litre".` Put the values in the equation, `K_(c) = ([H_(2)][I_(2)])/([HI]^(2)` and CALCULATE x.