InterviewSolution
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InterviewSolution
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Calculate the degree of hydrolysis of 0.04 M solution of `NH_(4) CI" of " pH =5.28` |
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Answer» Correct Answer - `1.312 xx 10^(-4)` `pH =5.28 " or " log [(1)/(H^(+))] =5.28` `[(1)/(H^(+))] = " Antilog " 5.28 " or " [H^(+)] = " Antilog " (-5.28)` `[H^(+)] = " Antilog " (bar(6).72) =5.248 xx 10^(-6)` Degree of hydrolysis `(h) =[[H^(+)]]/(C) = (5.248 xx 10 ^(-6))/(0.04) =1.312 xx 10^(-4)` |
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