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InterviewSolution
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Calculate the degree of ionization of pure water at `25^@C`. |
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Answer» Strategy: The degree of ionization of pure water `(alpha)` is the ratio of ionized water to that of unionized water. Solution: The density of pure water is `1g mL^(-1)` or `1000gL^(-1)`. The molar mass of water is `18gmol^(-1)`. Thus, the molarity of pure water can be given as `C_(H_2O)=(d_(H_2O))/("Molar mass"_(H_2O))=(1000gL^(-1))/(18gmol^(-1))` Now, we can calculate the degree of ionization of pure water as `alpha=(C_(H^+))/(C_(H_2O))` or `(C_(OH^-))/(C_(H_2O))=(1.0xx10^-7)/(55.5)` `=1.8xx10^-9` |
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