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Calculate the density of `NH_(3)` at `30^(@)C` and 5 atm pressure.A. `3.42 g L^(-1)`B. `2.42 g L^(-1)`C. `1.71 g L^(-1)`D. `3.84 g L^(-1)` |
Answer» Correct Answer - A `P = (dRT)/(M)` `d = (PM)/(Rt) = (5 xx 17)/(0.0832 xx 300) = 3.42 g L^(-1)` |
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