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Calculate the density of silver which crystallizes in a face-centred cubic structure. The distance between the nearest silver atoms in this structure is 287 pm. (Molar mass of Ag =`107.87 " g mol"^(-1), N_A=6.02xx10^23 "mol"^(-1)`) |
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Answer» Correct Answer - `10.71 "g cm"^(-3)` For FCC, `d=a/sqrt2` or a=`sqrt2`d=1414 x 287 pm = 406 pm , Z=4, M=`107. 87 "g mol"^(-1)` `rho=(ZxxM)/(a^3xxN_0)=(4xx107.87 "g mol"^(-1))/((406xx10^(-10) cm)^3xx(6.02xx10^23 mol^(-1)))=10.71 g cm^(-3)` |
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