Calculate the difference between the two specific heats of nitroge, given that the density of nitrogen at N.T.P is 1.25 g/litre and J = 4200 J/kcal. Express it in kcal/kgK.

Calculate the difference between the two specific heats of nitroge, gi

1.	Calculate the difference between the two specific heats of nitroge, given that the density of nitrogen at N.T.P is 1.25 g/litre and J = 4200 J/kcal. Express it in kcal/kgK.
Answer» Solution :The differncein SPECIFIC heats, `r=(P)/(rho T)`. `P= 1.013xx10^(5)N//m^(2), T=273K`, `rho=` density of the gas `rho = 1.25 XX (10^(-3) kg)/( 10^(3)cm^(3)) =(1.25 xx 10^(-3) kg)/( 10^(3) xx 10^(-6) m^(3))= 1.25 kg//m^(3)` `:.r=(1.013 xx 10^(5))/(1.25 xx 273) = 296.8J//kgK` `r=(296.8)/( 4200) "kcal"//kgK=0.07068`kcal/kg K. `:.` The difference of specific heats = 0.0768 kcal/kg K.