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Calculate the difference in osmotic pressure of \( 0.2 M Na _{2} SO _{4} \) and \( 0.5 M \) glucose solution at \( 27^{\circ} C \), assuming complete dissociation of \( Na _{2} SO _{4} \). |
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Answer» As we know Osmotic pressure \(\pi = iCRT\) \(i = \) Vant's Hoff factor For Na2SO4, \(i = 3\) For glucose, \(i = 1\) ∴ \(\pi _{Na_2SO_4} = 3 \times 0.2 \times 0.082 \times 300 \,atm\) \(= 14.76 \, atm\) \(\pi _{glucose} = 1 \times 0.5 \times 0.082 \times 300 \,atm\) \(= 12.3 \, atm\) Hence, difference in osmotic pressure = 14.76 - 12.3 = 2.46 atm. |
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