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Calculate the difference in temperature between the water at the top and bottom of a water fall 200 m high. Specific heat capacity of water 42000 J kg ^(-1) K ^(-1). |
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Answer» <P> SOLUTION :P.E. of water at a height `h = mgh``= m XX 9.8 xx 200 = 19 60 MJ` Using this P.. LET the temperature of water rise by `Delta T` `Delta Q = mc Delta T` `1960 m = m xx 4200 xx Delta T` `Delta T = (19 60)/(4200) = 0.4667 K` |
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