1.

Calculate the difference in temperature between the water at the top and bottom of a water fall 200 m high. Specific heat capacity of water 42000 J kg ^(-1) K ^(-1).

Answer»

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SOLUTION :P.E. of water at a height `h = mgh`
`= m XX 9.8 xx 200 = 19 60 MJ`
Using this P.. LET the temperature of water rise by `Delta T`
`Delta Q = mc Delta T`
`1960 m = m xx 4200 xx Delta T`
`Delta T = (19 60)/(4200) = 0.4667 K`


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