Calculate the distance between (111) planes in a crystal of calcuim . Repeat the calculation for (222) planes . Which planes are closer? (a=0.556 nm)

Calculate the distance between (111) planes in a crystal of calcuim .

1.	Calculate the distance between (111) planes in a crystal of calcuim . Repeat the calculation for (222) planes . Which planes are closer? (a=0.556 nm)
Answer» SOLUTION :`d=a/(sqrt(h^2+k^2+l^2))` `d_111=0.556/(sqrt(1^2+1^2+1^2))=0.556/sqrt3`=0.321 nm `d_222=0.556/(sqrt(2^2+2^2+2^2))=0.556/sqrt12`=0.161 nm Thus (222) planes are CLOSER and their distance of separation is HALF of that of (111) planes