InterviewSolution
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InterviewSolution
| 1. |
Calculate the distance between (111) planes in a crystal of calcium. Repeat the calculation for (222) planes. Which palnes are closer ? (a = 0.556 nm) |
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Answer» ` d = a/(sqrt(h^(2) +k^(2) +l^(2))` ` d_(111) = 0.556/(sqrt(1^(2) +1^(2) +1^(1))) = 0.556/sqrt12 = 0.161 nm` Thus (222) planes are closer and their distance of separation is half of that of (111) planes. |
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