InterviewSolution
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InterviewSolution
| 1. |
Calculate the distance between (111) planes in a crystal of calcuim . Repeat the calculation for (222) planes . Which planes are closer ? (a=0.556 nm) |
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Answer» `d=a/(sqrt(h^2+k^2+l^2))` `d_111=0.556/(sqrt(1^2+1^2+1^2))=0.556/sqrt3`=0.321 nm `d_222=0.556/(sqrt(2^2+2^2+2^2))=0.556/sqrt12`=0.161 nm Thus (222) planes are closer and their distance of separation is half of that of (111) planes |
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