Calculate the e.m.f. of the cell, `Mg//Mg^(2+)(0.1 M)||Ag^(+)(1.0xx10^(-3)M)//Ag` The values of `E_(Mg^(2+)//Mg)^(@)` and `E_(Ag^(+)//Ag)^(@)` are -2.37`" V"` and +0.80`" V "` respectively.

Calculate the e.m.f. of the cell, `Mg//Mg^(2+)(0.1 M)||Ag^(+)(1.0xx10^

1.	Calculate the e.m.f. of the cell, `Mg//Mg^(2+)(0.1 M)\|\|Ag^(+)(1.0xx10^(-3)M)//Ag` The values of `E_(Mg^(2+)//Mg)^(@)` and `E_(Ag^(+)//Ag)^(@)` are -2.37`" V"` and +0.80`" V "` respectively.
Answer» Correct Answer - 3.02`" V "` Cell reaction : `Mg(s)+2Ag^(+)(1.0xx10^(-3)M) to Mg^(2+)(0.1 M)+2Ag(s)` `E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Mg^(2+)])/([Ag^(+)]^(2))=[+0.8-(-2.37)]-(0.0591)/(2)"log"(0.1)/(1xx10^(-3))^(2)` `=3.17-0.02955" log "10^(5)=3.17-0.02955xx5` `=3.17-0.14775=3.02225" V "=3.02 "V "`.

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Calculate the e.m.f. of the cell, `Mg//Mg^(2+)(0.1 M)||Ag^(+)(1.0xx10^(-3)M)//Ag` The values of `E_(Mg^(2+)//Mg)^(@)` and `E_(Ag^(+)//Ag)^(@)` are -2.37`" V"` and +0.80`" V "` respectively.

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