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Calculate the electronegativity of fluorine from the following data: `E_(H-H) = 104.4 kcal mol^(-1), E_(F-F) = 36.6 kcal mol^(-1)` `E_(H-F) = 134.3 kcal mol^(-1), chi_(H) = 2.1` |
Answer» Correct Answer - `[3.8752]` `[x_(F) - 2.1 = 0.208 sqrt(134.6 - sqrt(104.2 xx 36.3)) x_(F) = 3.87]` |
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