Calculate the emf for the following cell at 298 K. `Cd//Cd^(2+)(0.1 M) || Ag^(+)(0.1 M)//Ag` `"Given"E_(Cd^(2+)//Cd)^(@)=-0.40" V ",E_(Ag^(+)//Ag)^(@)=0.80" V "`

Calculate the emf for the following cell at 298 K. `Cd//Cd^(2+)(0.1 M)

1.	Calculate the emf for the following cell at 298 K. `Cd//Cd^(2+)(0.1 M) \|\| Ag^(+)(0.1 M)//Ag` `"Given"E_(Cd^(2+)//Cd)^(@)=-0.40" V ",E_(Ag^(+)//Ag)^(@)=0.80" V "`
Answer» Correct Answer - 1.17 V Cell reaction : `Cd(s)+2Ag^(+)(0.1" M") to Cd^(2+)(0.1" M")+2Ag(s)` `E_(cell)=E_(cell)^(@)-(0.0591)/(n)"log"([Cd^(2+)])/([Ag^(+)]^(2))=[(0.8)-(-0.4)]-(0.0591)/(2)"log"(0.1)/((0.1)^(2))` `=1.20-0.02955=1.17" V "`

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Calculate the emf for the following cell at 298 K. `Cd//Cd^(2+)(0.1 M) || Ag^(+)(0.1 M)//Ag` `"Given"E_(Cd^(2+)//Cd)^(@)=-0.40" V ",E_(Ag^(+)//Ag)^(@)=0.80" V "`

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