Calculate the emf of the cell at `25^(@)C` `Cr|Cr^(3+)(0.1M)||Fe ^(2+)(0.01M) |Fe,` given that `E_(Cr^(3+)//Cr )^(0)=-0.74V and E_(Fe ^(2+)//Fe )^(0)=-0.44V`

Calculate the emf of the cell at `25^(@)C` `Cr|Cr^(3+)(0.1M)||Fe ^(2+)

1.	Calculate the emf of the cell at `25^(@)C` `Cr\|Cr^(3+)(0.1M)\|\|Fe ^(2+)(0.01M) \|Fe,` given that `E_(Cr^(3+)//Cr )^(0)=-0.74V and E_(Fe ^(2+)//Fe )^(0)=-0.44V`
Answer» Given cell is `Ce\|Cr _((0.1M))^(+3)\|\|Fe_((0,01M))^(+2)\|Fe` `E^(0) of Cr ^(+3)//Cr =-0.74V` `E^(0)of F^(+2)//Fe =-0.44V` `E_(Cr^(3)//C)=E^(0) +(0.059)/(3)log _(10) [Cr^(+3)]` `=-0.74+(0.054)/(3)log 0.1` `=-0.76V` `E_(Fe^(+2)//Fe) =-0.44+(0.059)/(2)log 0.01` `=-0.44-0.059=-0.499V` EMF of cells `=E_(RHS) -E_(LHS)` `=(-0.499) -(-0.76)=0.261V`

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Calculate the emf of the cell at `25^(@)C` `Cr|Cr^(3+)(0.1M)||Fe ^(2+)(0.01M) |Fe,` given that `E_(Cr^(3+)//Cr )^(0)=-0.74V and E_(Fe ^(2+)//Fe )^(0)=-0.44V`

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