Calculate the emf of the cell consisting the following half cells `Al//Al^(3+)(0.001M), Ni//Ni^(2)(0.50M).` Given that `E_(Ni^(2+)//Ni)^(0)=-0.25V` `E_(Al^(3+)//Al)=-1.66V(log 8xx10^(-6)=-5.0969).`

Calculate the emf of the cell consisting the following half cells `Al/

1.	Calculate the emf of the cell consisting the following half cells `Al//Al^(3+)(0.001M), Ni//Ni^(2)(0.50M).` Given that `E_(Ni^(2+)//Ni)^(0)=-0.25V` `E_(Al^(3+)//Al)=-1.66V(log 8xx10^(-6)=-5.0969).`
Answer» Given `E^(0)of Al^(+3)//Al=-1.66V` `E^(0)of Ni^(+2)//Ni=-0.25V` Cell pepresentation `Al //Al_(""(0,001M))^(+3)\|\|Ni_(""(0.50M))^(+2)\|Ni` Nernst equation is `E_(A l ^(+_3)//Al)+(0.059)/(n) log [Al ^(+3)]` `=-1.66 +(0.59)/(3)log 0.001=-1.66-0.59=-1.719V` `E _(Ni^(+2)//Ni)= E_(Ni^(+2)//Ni)+(0.059)/(n) log [Ni ^(+2)] ` `=- 0.25 +(0.059)/(2)log [0.5]` `=-0.25-0.0295xx0.3010=-0.25-0.0088795=-0.25888` EMF of cell `=E _(RHS ) -E _(LHS)` `=-0.25888-(-1.719)=1.46012V`

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Calculate the emf of the cell consisting the following half cells `Al//Al^(3+)(0.001M), Ni//Ni^(2)(0.50M).` Given that `E_(Ni^(2+)//Ni)^(0)=-0.25V` `E_(Al^(3+)//Al)=-1.66V(log 8xx10^(-6)=-5.0969).`

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