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Calculate the emf of the following cell at 298 K.Zn(s)∣Zn2+(aq, 0.1 M)∥Ag+(aq, 0.01 M)∣ Ag(s)Given: E0Zn2+/Zn = −0.76 VE0Ag+/Ag =+0.80 V |
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Answer» Calculate the emf of the following cell at 298 K. |
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