1.

Calculate the emf of the following cell at 298 K.Zn(s)∣Zn2+(aq, 0.1 M)∥Ag+(aq, 0.01 M)∣ Ag(s)Given: E0Zn2+/Zn = −0.76 VE0Ag+/Ag =+0.80 V

Answer»

Calculate the emf of the following cell at 298 K.

Zn(s)Zn2+(aq, 0.1 M)Ag+(aq, 0.01 M) Ag(s)

Given:

E0Zn2+/Zn = 0.76 V

E0Ag+/Ag =+0.80 V



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