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Calculate the emf of the following concentration cell at `25^(@)C`: `Ag(s)|AgNO_(3) (0.01 M)||AgNO_(3) (0.05 M)|Ag (s)`A. 0.828VB. 0.0413VC. `-0.0413` VD. `-0.828` V |
Answer» Correct Answer - B `E=E^@-0.0591/n` log Q `E^@`=0 for all concentration cells =`0-0.0591/1 "log"(0.01/0.05)`=0.0413 V |
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