Calculate the empinaical and molecular formula compound containing 76.6% carbon 6.38%hydbogen and rest oxygen vapoun density is 47

Calculate the empinaical and molecular formula compound containing 7

1.	Calculate the empinaical and molecular formula compound containing 76.6% carbon 6.38%hydbogen and rest oxygen vapoun density is 47
Answer» Given conditions,Carbon % = 76.5%HYDROGEN% = 6.38%OXYGEN% = 100 - (76.5 + 6.38) = 100 - 82.88 = 17.12%Now, Refers to the attachment for the Empirical Formula Chart.Empirical Formula is C₆H₆O.Empirical Formula Mass = 12 × 6 + 1 × 6 + 16 = 94 gMolecular Mass = 2 × Vapor Density∴ MOLECULAR Mass = 2 × 47∴ Molecular Mass = 94 g.∴ n = Molecular Mass/Empirical Formula Mass = 94/94 = 1∴ Molecular Formula = 1 × C₆H₆O = C₆H₆OHope it helps.