Calculate the empirical and molecular formula of a compound containing 76.6% carbon, 6.38 % hydrogen and rest oxygen its vapour density is 47

Calculate the empirical and molecular formula of a compound containing

1.	Calculate the empirical and molecular formula of a compound containing 76.6% carbon, 6.38 % hydrogen and rest oxygen its vapour density is 47
Answer» Solution : Emperical formula=`C_(6(H_(6)O` VAPOUR DENSITY=47 `:.`Molecular mass= `2 xx` vapour density `=2xx47=94` Molecular formula= Empirical formula `xx n` `n=("molecular mass")/("Emperical frmular mass")=94/94=1` `:.` Molecular formula=`C_(6)H_(6)O`