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Calculate the enegry of an electron in the first Bohr orbit if a hydrogen atom. Strategy: Use Eq. to obtain directly the energy of the lowest stationary state (or ground state). |
Answer» Assume `n = 1`, take `Z = 1`, and insert the values of the constants of obtain `E_(1) =- ((2)(3.14)^(2)(1)^(2)(4.8xx10^(-10)esu)^(4)(9.11xx10^(-18)g))/((1)^(2)(6.63xx10^(-27)erg s)^(2))` `=- 2.188 xx 10^(-11) "erg atom"^(-1)` `=- 2.188 xx 10^(-18) J "atom"^(-1)` `=- 13.6eV "atom"^(-1)` `=- 1312 kJ mol^(-1)` |
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