1.

Calculate the energy in corresponding to light of wavelength 45 nm. (Planck’s constant h = 6.63 xx 10^(-34) JS, Speed of light C = 3 xx 10^(8)ms^(-1) )

Answer»

`6.67xx10^(15)`
`6.7xx10^(11)`
`4.42xx10^(-15)`
`4.42xx10^(-18)`

SOLUTION :`E=(hc)/(LAMBDA)=(6.63xx10^(-34)xx3xx10^(8))/(45xx10^(-9))=4.4xx10^(-18)` J


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